it is a basic element in graphics. step 1: read the input of the 2 end points of the line as (x1, y1) & (x2, y2) such that x1 != x2 and y1 != y2eval(ez_write_tag([[336,280],’thecrazyprogrammer_com-box-3′,’ezslot_0′,113,’0′,’0′])); a crazy computer and programming lover. all programs are awesome, thanks for such a nice blog, where can i get all the commands used in graphics.h ???
or x and y are used to give it postiion, you things like that, a simple way to explain this might be that you’re simply counting the number of ‘steps’ to take between point 1 and point 2, calculating the x-axis length and y-axis of each ‘step’, and then looping to add that step length to x and y respectively for each step between point 1 to point 2. unless i’m mistaken, your algorithm here (and your bresenham algorithm too) only works when x2 > x1 and y2 > y1. it’s easy to fix for any two arbitrary points: simply subtract the axis length instead of adding it (dx or dy), in the case that x1 > x2 or y1 > y2 respectively. how to run this on macos or linux?? this would help you first: go to the working directory (place your file is stored) second: open cmd(command promt there) or press win+r and then enter cmd in the search box then manually change the path (it will be c: by default) third: when you are in working directory enter gcc “filename.c” -o “filename.exe” (if it is a c program) if the file compiles correctly then press ./”filename.exe” this will run your code and please make sure that you have set up your path for gcc and remove the quotes while entering the filename.
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